
What are the chances of all of Lucifer's angels rebelling and none of the others?
Assume 12 archangels with angels under each one.
Assume that God endowed each angel with a free will and that each angel has 1 chance in 2 of rebelling.
What are the chances of all of the angels under 1 archangel rebelling but none of the angels under any of the oher 11 archangels rebelling?
Is it 1 over 2 to the power of the number of angels?
Or is it more complicated than that?
Best answer:
Answer by MJ
slim to none you moron!
got em!
Know better? Leave your own answer in the comments!
Pandora Charm Authentic Treasure Angel of Hope Christmas Tree Silver ALE 925| US $31.00 (17 Bids) End Date: Sunday May-20-2012 12:39:10 PDT Bid now | Add to watch list |
| US $18.45 End Date: Sunday May-20-2012 12:39:12 PDT Buy It Now for only: US $18.45 Buy it now | Add to watch list |
Related posts:
- What do You think the Author Thaddeus Jean meant by taking Lucifers sight?
- How was Satan able to convince the other angels to follow him?
- Q&A: How old is the concept of the existence of angels?
- What are some names of good fiction novels about angels?
- Christians, How is it that the angels will gather the elect from the four winds?

50%.
The chance that a particular angel rebels is 50%. Once that angels rebels, the chance of the next angel rebelling is still 50% (the angel will or won’t rebel).
Thus, the answer to all the questions is 50%.
I wasn’t aware that angels had free will, so the scenario can’t happen.
and if all the angels had the browser problems you are having, i wouldn’t be surprised if all of them rebelled. :p
and free will is always complicated – so yeah – i don’t think you could figure it out anyway…
I am glad to answer a Mathematical question of a Top Contributor in the Classical Forum, many of whose competent answers I have read visiting that forum.
The question in the title: ‘What are the chances of all of Lucifer’s (personally Lucifer’s) angels . . .’ is not identical to that below in the text: ‘ . . . of all of the angels under 1 archangel (any of the 12 archangels, arbitrary only one chosen) . . .’ – the answer to the second one is a probability 12 time larger than the answer to the first one. If we assume that angels are distinguishable (each has his own personality) and each angel rebels with probability of 1/2 = 0.5 independently from the others, then the answer to the first question is indeed 1/2 to the power of the number of angels. Indeed the required probability is
P[(1st Lucifer's angel rebelling) and (2nd Lucifer's angel rebelling) and . .
. . and (last Lucifer's angel rebelling) and (1st Gabriel's angel not rebelling) and . .
. . and (last archangel's last angel not rebelling)] =
= (1/2) * (1/2) * . . * (1/2) * (1 – 1/2) * . . (1 – 1/2)
The factors here are as many as are angels.
The same probability is that all of archangel Gabriel’s angels rebelling and none of the others etc. for every archangel. That’s why the answer to the 2nd question is 12 times the above number.
I agree completely with Duke’s answers and would like to take a moment to respond to switch’s reasoning that angels have no free will. If you accept the account given in the bible of how lucifer rebelled against god’s will, then angels, at least for a time, had free will, otherwise it would not have been possible for him to have rebelled. Further your argument is mindless and pedantic and has no real bearing on the question, as it can be viewed and answered from a hypothetical point of view and thus does not require you to believe anything set forth in the question, such as the existence of angels.